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30x+16=7x^2
We move all terms to the left:
30x+16-(7x^2)=0
determiningTheFunctionDomain -7x^2+30x+16=0
a = -7; b = 30; c = +16;
Δ = b2-4ac
Δ = 302-4·(-7)·16
Δ = 1348
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1348}=\sqrt{4*337}=\sqrt{4}*\sqrt{337}=2\sqrt{337}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{337}}{2*-7}=\frac{-30-2\sqrt{337}}{-14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{337}}{2*-7}=\frac{-30+2\sqrt{337}}{-14} $
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